Variation of 'g' with Depth

Consider a body of mass m, lying on the surface of the Earth of radius R and mass M. Let g be the acceleration due to gravity at that place.
Let the body be taken to a depth d from the surface of the Earth. Then, the force due to gravity acting on this body is only due to the sphere of radius R.
(R - d). If g^| is the acceleration due to gravity at depth 'd'

Let the Earth be of uniform density r and its shape be a perfect sphere.
(Where r is the density of the Earth)


Comparing g^| and g

The acceleration due to gravity decreases with increase in depth.
If d = R, then g^| = 0. Weight of a body at the centre of the Earth is zero.